[Re:02] m resolved partial DOS

Posted on : November 15, 2010 (Mon) 23:06:49

by Jerzy Goraus

Thank you for answer.
So to be sure,
wkc(2) is for m=-1 ,
wkc(3) for m=0 and wkc(4) for m=1
and then wkc(5) for m=-2, wkc(6) for m=-1 and so on ?

sincerely,
Jerzy Goraus